What is the change in the momentum of the body if a force of 10 kN acted on it for 0.3 seconds?
| June 29, 2021 | education
The task:
t – 0.3 sec;
F – 10 kN;
dP -? N * sec.
Calculation formula:
dP = F * t, where
F – acting force, N;
t – time of force action, sec.
For calculations, you need to know that 10 kN = 10,000 N.
We solve: dP = 10000 * 0.3 = 3000 N * sec.
Answer: the change in the impulse of the body is equal to dP = 3000 H * sec.
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