What is the charge of electrons in a 200g gold bar?

Given: m (mass of the considered ingot) = 200 g (in SI m = 0.2 kg).

Reference data: M (molar mass of gold) ≈ 0.197 kg / mol; Na (Avogadro’s number) = 6.02 * 10 ^ 23 mol-1; e (electron charge) = -1.6 * 10 ^ -19 C; gold exists in the form of monatomic molecules; 79 electrons move along the six orbits of the atom (Z = 79).

The electron charge in the considered gold ingot is calculated by the formula: q = N * Z * e = m * Na * Z * e / M.

Calculation: q = 0.2 * 6.02 * 10 ^ 23 * 79 * (-1.6 * 10 ^ -19) / 0.197 ≈ -7.73 * 10 ^ 6 Cl.



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