What is the charge of phosphorus in the P2O5 + KOH reaction?

In order to find out what charge phosphorus has in the interaction of potassium hydroxide and pentavalent phosphorus oxide, we need to draw up the molecular equation of the reaction and then draw up the ionic equation of the reaction. During the reaction, a potassium phosphate salt is formed and water is released. The molecular equation of the reaction can be written as follows:

6 KOH + P2O5 = 2 K3PO4 + 3 H2O

This reaction requires equalization, for this we need to put 6 in front of the potassium hydroxide, and in the reaction products, we put the number two in front of the salt, and the number 3 in front of the water.

The ionic reaction equation can be written as follows:

6 K⁺ + 6 OH^– + P₂O₅ = 6 K⁺ + 2 PO₄ ^3- + 3 H₂O

P₂O₅ + 6 OH^–  = 3 H₂O + 2 PO₄ ^3- .