What is the chemical amount of KOH required to obtain potassium carbonate with a mass of 20 grams?

The reaction for the synthesis of potassium carbonate from its hydroxide is described by the following chemical reaction equation:

2KOH + CO2 = К2CO3 + Н2О

From 2 moles of potassium hydroxide, 1 mole of potassium carbonate is synthesized.

Let’s calculate the required chemical amount of a substance of potassium carbonate.

М К2СО3 = 39 x 2 + 12 + 16 x 3 = 138 grams / mol;

N K2CO3 = 20/138 = 0.145 mol;

To get such an amount of carbonate, you need to take 0.145 x 2 = 0.29 mol of potassium hydroxide.

Let’s calculate its weight. To do this, we multiply the amount of the substance by its molar mass.

M KOH = 39 + 16 + 1 = 56 grams / mol;

m KOH = 0.29 x 56 = 16.24 grams;