What is the chemical amount of lithium oxide required to obtain a lithium base with a mass of 2.4 g?

In accordance with the condition of the problem, we will compose the reaction equation and arrange the coefficients;
Li2O + 2H2O = 2LiOH – the reaction of the compound, lithium hydroxide was obtained;
M (Li2O) = 29.8 g / mol;
M (LiOH) = 23.9 g / mol;
Determine the number of moles of lithium hydroxide, if the mass is known:
Y (LiOH) = m / M = 2.4 / 23.9 = 0.1 mol;
Let’s make a proportion according to the equation:
X mol (Li2O) – 0.1 mol (LiOH);
-1 mol -2 mol hence, X mol (LiOH) = 1 * 0.1 / 2 = 0.05 mol.
Answer: The reaction requires 0.05 mol of lithium oxide.