What is the cost of electricity consumed by an electric iron with a power of 1200 W

What is the cost of electricity consumed by an electric iron with a power of 1200 W for 1 hour of continuous operation if the electricity tariff is 0.9 r per 1 kW * h?

1) The amount of electricity consumed by the iron in 1 hour:

E = P * t, where P is the power of the electric iron (P = 1200 W), t is the operating time of the iron (t = 1 h).

E = R * t = 1200 * 1 = 1200 W * h = 1.2 kW * h.

2) The cost of the electricity consumed by the iron:

S = E * T, where T is the tariff (T = 0.9 rubles per 1 kW * h).

S = E * T = 1.2 * 0.9 = 1.08 rubles.

Answer: The cost of electricity will be 1.08 rubles.