# What is the cross-sectional area of an aluminum wire, the relative elongation of which became equal to 0.004 after a 7 kg

What is the cross-sectional area of an aluminum wire, the relative elongation of which became equal to 0.004 after a 7 kg load was suspended from its free wire? Young’s modulus of aluminum is 7 * 10 ^ 10 Pa.

To determine the value of the cross-sectional area of the specified aluminum wire, we use the formula: F = E * S * Δl / l = E * S * ε = m * g, from where we express: S = m * g / (E * ε).

Variables and constants: m is the mass of the suspended load (m = 7 kg); g – acceleration of gravity (g = 9.81 m / s2); E – Young’s modulus for aluminum (according to the condition E = 7 * 10 ^ 10 Pa); ε – relative elongation (ε = 0.004).

Calculation: S = m * g / (E * ε) = 7 * 9.81 / (7 * 10 ^ 10 * 0.004) = 0.24525 * 10 ^ -6 m2 = 0.24525 mm2.

Answer: The cross-sectional area of the specified aluminum wire is 0.24525 mm2. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.