What is the current in the 5 ohm resistor and the voltage at its ends of 10 V?
| December 2, 2020 | education
Ohm’s law U = IR —- I = U / R
Therefore, taking this into account, we substitute what we need in the formula:
I = 10V / 5Ω = 2A – current in the pesistor
Answer: 2A
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