What is the current strength in a straight conductor 1.0 m long, placed in a uniform magnetic field with an induction

| September 25, 2021 | education

What is the current strength in a straight conductor 1.0 m long, placed in a uniform magnetic field with an induction of 1.5 * 10 ^ -3 T, if a force of 2.1 * 10 ^ -3 H acts on this conductor from the side of the field? The angle between the direction of the electric current and the induction vector = 45 degrees.

To determine the value of the current in the taken straight conductor, we will use the formula: Fa = B * I * l * sinα and I = Fa / (B * l * sinα).

Values of variables: Fa – Ampere force (Fa = 2.1 * 10-3 N); B – field induction (B = 1.5 * 10-3 T); l is the length of the specified conductor (l = 1 m); α is the angle between the given induction vector and the direction of the current (α = 45º).

Calculation: I = Fa / (B * l * sinα) = (2.1 * 10-3) / (1.5 * 10-3 * 1 * sin 45º) = 1.98 A.

Answer: The current in the taken straight conductor is 1.98 A.



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