What is the current strength in an electric lamp of a flashlight if the resistance
| March 8, 2021 | education
What is the current strength in an electric lamp of a flashlight if the resistance of the filament is 16.6 and the lamp is connected to a 2.5 volt battery?
To determine what the current I in the electric lamp of a pocket flashlight is equal to, if the resistance of the filament is R = 16.6 ohms and the lamp is connected to a battery with a voltage of U = 2.5 Volts, we use Ohm’s law for a section of the circuit: I = U: R. Substitute the values of physical quantities in the formula and make calculations: I = 2.5 V: 16.6 Ohm ≈ 0.15 A.
Answer: ≈ 0.15 A is the current in the electric lamp of the flashlight.
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