What is the current strength in the electric lamp of a flashlight if the resistance
| September 19, 2021 | education
What is the current strength in the electric lamp of a flashlight if the resistance of the filament is 0.0166 kOhm and the lamp is connected to a 3.5 V battery?
To calculate the desired value of the current in the lamp of the used flashlight, we will use Ohm’s law for the section of the circuit: I = U / R.
Variables: U – voltage supplied from the battery (U = 3.5 V); R – resistance (R = 0.0166 kΩ = 16.6 Ω).
Let’s make a calculation: I = U / R = 3.5 / 16.6 = 0.211 A.
Answer: A current of 0.211 A flows through the lamp of the flashlight used.
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