What is the density of a body if it floats in water, submerged by 0.8 of its volume?
| July 16, 2021 | education
Since the specified body is in equilibrium, the value of its density is determined using the equality: Fа = Fт and ρw * g * Vlim = m * g = ρt * V * g, whence ρt = ρw * Vlim / V.
Variables and constants: ρw – water density (consider ρw = 1000 kg / m3); Vlim – a part of the specified body immersed in water (Vlim = 0.8V).
Calculation: ρt = ρw * Vlim / V = 1000 * 0.8V / V = 800 kg / m3.
Answer: the density of the specified body is 800 kg / m3.
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