To determine the value of the oxygen density under normal conditions, we apply the Mendeleev-Clapeyron law: P * V = m * R * T / M and m / V = ρk (oxygen density) = Pn * Mo2 / (R * Tn).
Constant values: Pn – pressure (Pn = 101325 Pa); Mo2 is the molar mass of oxygen (according to the condition Mo2 = 0.032 kg / mol); R – universal gas constant (R = 8.31 J / (mol * K)); Tnu – temperature (Tnu = 273.15 K).
Calculation: ρc = Pn * Mo2 / (R * Tn) = 101325 * 0.032 / (8.31 * 273.15) = 1.428 kg / m3.
Answer: Under normal conditions, the density of oxygen, according to the calculation, is 1.428 kg / m3.
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