What is the density of the liquid into which a body with a volume of 3 m3 was immersed

What is the density of the liquid into which a body with a volume of 3 m3 was immersed if the Archimedean force acting on the body is 30000N.

Given:

V = 3 m3 (cubic meters) – the volume of a body immersed in some liquid;

A = 30000 Newton – Archimedean (buoyancy) force acting on the body when it is immersed;

g = 10 N / kg (Newton per kilogram) – acceleration due to gravity (approximate value).

It is required to determine ro (kg / m3) – the density of the liquid.

Since the condition of the problem is not specified, we assume that the immersion of the body was complete. Then, to determine the density, you must use the following formula:

A = ro * g * V, from here we find that:

ro = A / (g * V) = 30,000 / (10 * 3) = 3000/3 = 1000 kg / m3 (kilogram per cubic meter).

Answer: the density of the liquid is 1000 kg / m3.