What is the depth of the cork in the bottom of the vessel with water if a force of 29.4 N

What is the depth of the cork in the bottom of the vessel with water if a force of 29.4 N acts on the cork with an area of 15 cm2 from the water side?

These tasks: S (area of the considered plug) = 15 cm2 (in SI S = 15 * 10-4 m2); F (force acting on the plug from the water side) = 29.4 N.

Reference values: ρw (density of water in the vessel) = 1000 kg / m3; g (acceleration due to gravity) ≈ 9.8 m / s2.

We express the depth of the plug in the vessel from the equality: ρw * g * h = P = F / S, whence h = F / (S * ρw * g).

Let’s calculate: h = 29.4 / (15 * 10-4 * 1000 * 9.8) = 2 m.

Answer: The depth of the considered plug is 2 m.