What is the depth of the well if a stone falls into it 2.5s.

Initial data: t (the duration of the fall of the stone to the bottom of the well) = 2.5 s; the fall of the stone into the well is considered free (V0 = 0 m / s).

Reference values: g (acceleration of gravity) ≈ 10 m / s2 = a (acceleration of a stone).

The depth of the well is determined by the formula: H = S = V0 * t + 0.5a * t ^ 2 = 0.5 * g * t ^ 2.

Calculation: H = 0.5 * 10 * 2.5 ^ 2 = 31.25 m.

Answer: The depth of the well is 31.25 m.