What is the distance between houses A and B, located on two mutually perpendicular streets

What is the distance between houses A and B, located on two mutually perpendicular streets, if house A is located 2 km from the intersection, and B – 1.5 km from the same intersection.

the houses are located so that together with the intersection they form a right-angled triangle, and the distance between them is its hypotenuse.

The square of the hypotenuse is equal to the sum of the squares of the legs.

AB ^ 2 = 2 ^ 2 + 1.5 ^ 2 = 4 + 2.25 = 6.25.

AB = √6.25 = 2.5 km is the distance between houses.



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