What is the distance between two point charges 0.002 C and 0.001 C if the force of their interaction is 10000 N?
| September 7, 2021 | education
Data: q1 (value of the first chiseled charge) = 0.002 C; q2 (the value of the second chiseled charge) = 0.001 C; F (force of interaction between two given point charges) = 10000 N.
Constants: k (proportionality coefficient, air) = 9 * 109 N * m2 / Cl2.
The distance between two given point charges is determined using the Coulomb law: F = k * q1 * q2 / R ^ 2, whence R = √ (k * q1 * q2 / F).
Calculation: R = √ (9 * 109 * 0.002 * 0.001 / 10000) = 1.34 m.
Answer: The distance between charges is 1.34 m.
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