What is the efficiency of a heat engine if it receives a count from the heater? heat, equal to 6 kJ

What is the efficiency of a heat engine if it receives a count from the heater? heat, equal to 6 kJ, and gives the refrigerator a count. heat equal to 4.8kJ?

To determine the value of the efficiency of the specified heat engine, we will use the formula: η = 1 – Qhol / Qload.

Values of variables: Qhol – given heat to the refrigerator (Qhol = 4.8 kJ); Qheat – heat received from the heater (Qheat = 6 kJ).

Calculation: η = 1 – Qhol / Qload = 1 – 4.8 / 6 = 0.2 (20%).

Answer: The efficiency of this heat engine is 20%.



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