What is the efficiency of an ideal heat engine if the machine does 50 J of useful work per cycle and gives the refrigerator 100 J?
| February 28, 2021 | education
The energy received per cycle will be equal to the sum:
E = 50 + 100 = 150 J.
Then the efficiency will be:
(50/150) * 100 = 100/3 = 33%.
Answer: the required efficiency is 33%.
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