# What is the efficiency of an ideal heat engine if the temperature of the refrigerator is 100 ºС

September 30, 2021 | education

| **What is the efficiency of an ideal heat engine if the temperature of the refrigerator is 100 ºС, and the temperature of the heater is three times higher?**

The efficiency of an ideal heat engine can be calculated using the formula:

Efficiency = ((T1 – T2) / T1) * 100%, where T1 is the heater temperature (ºC), T2 is the refrigerator temperature (T2 = 100 ºC = 373 K).

Since the temperature of the heater is three times higher than the temperature of the refrigerator, then Т1 = 3 * Т2 = 3 * 100 = 300 ºС = 573 K.

Let’s calculate the efficiency:

Efficiency = ((T1 – T2) / T1) * 100% = (573 – 373) / 573) * 100% = (200/573) * 100% = 34.9%.

Answer. The efficiency of an ideal heat engine is 34.9%.

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