What is the efficiency of an inclined plane if the total work of lifting the load is 10kJ, and the useful work is 6kJ?

univerkov | March 12, 2021 | education

Initial data: Appol. (full work on lifting the load on an inclined plane) = 10 kJ (10 * 10 ^ 3 J); Apolezn. (useful work) = 6 kJ (6 * 10 ^ 3 J).

The efficiency of an inclined plane is calculated by the formula: η = (Apolezn./Apoln.) * 100%.

Calculation: η = (6 * 10 ^ 3 / (10 * 10 ^ 3)) * 100% = 60%.

Answer: The efficiency of this inclined plane is 60%.

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