What is the efficiency of the system of movable and fixed blocks, with the help of which a load

What is the efficiency of the system of movable and fixed blocks, with the help of which a load weighing 12 kg is lifted to a height of 6 m with a force of 66 N.

Task data: m (mass of the load lifted by the system) = 12 kg; h (lifting height) = 6 m; F (force applied to the load) = 66 N.

Reference values: g (acceleration due to gravity) = 9.81 m / s2.

The efficiency of the used system of blocks is calculated by the formula: η = Ap / Az = ΔEp / (F * S) = m * g * h / (F * 2 * h) = m * g / (2 * F).

Let’s calculate: η = 12 * 9.81 / (2 * 66) = 0.892 (89.2%).

Answer: The efficiency of the used block system is 89.2%.