What is the energy of the magnetic field of a coil with an inductance of 0.005 kH through which a current of 2000mA flows?
| July 2, 2021 | education
L = 0.005 kH = 5 H.
I = 2000 mA = 2 A.
W -?
The energy of the magnetic field of the coil through which the electric current flows is determined by the formula:
W = L * I ^ 2/2.
Where L is the inductance of the coil through which the current flows, I is the current in the coil.
W = 5 H * (2 A) ^ 2/2 = 10 J.
Answer: the energy of the magnetic field of the coil is W = 10 J.
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