What is the energy of the magnetic field of a coil with an inductance of 2H at a current strength of 200A.

The magnetic field energy of a given coil can be calculated using the following formula:

Wm = L * I ^ 2/2, where L is the given inductance of the coil (L = 2 H), I is the given current in the coil (I = 200 A).

Let’s make a calculation:

Wm = 2 * 200 ^ 2/2 = 40,000 J = 40 kJ.

Answer: The energy of the magnetic field of a given coil is 40 kJ.



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