What is the energy of the magnetic field of the coil, if its inductance is 400 mH, and the current strength = 2.0A

univerkov | December 2, 2020 | education

Given:
L = 400 mH = 4 * 10 ^ -1 H
I = 2A
Find: w
Decision:
The formula for the magnetic field energy of the coil looks like this:
w = (L * I ^ 2) / 2
We substitute our values into the formula, we get:
w = (4 * 10 ^ -1 * 4) / 2 = 8 * 10 ^ -1 = 0.8 (J)
Answer: w = 0.8 J

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.