What is the equivalent volume of oxygen? The combustion of 1.5 g of divalent metal requires 0.69 dm3 of oxygen.

| April 28, 2021 | education

What is the equivalent volume of oxygen? The combustion of 1.5 g of divalent metal requires 0.69 dm3 of oxygen. Calculate the molar mass equivalent, molar mass and atomic mass of this metal. If possible, with an explanation.

1. We will find the molar mass of the metal by the formula:

n = m M

M = n: m.

Let’s find the amount of oxygen by the formula.

Let’s compose the reaction equation.

2Me + O2 = 2MeO

There is 1 mole of oxygen for 2 mol of metal. Substances are in quantitative ratios of 2: 1.

This means that the amount of metal substance will be 2 times more than the amount of oxygen.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

Hence n = V: Vn.

n = 0.69: 22.4 L / mol = 0.031 mol.

n (Me) = 0.031 mol × 2 = 0.062 mol.

Let’s find the molar mass of the metal.

M = m: n.

M = 1.5 g: 0.062 mol = 24.19 g / mol.

Ar (Mg) = 24.

Answer: Mg.



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