What is the focal length of a biconvex lens with equal radii of curvature of 20 cm, made of glass with an absolute refractive index of 1.5?
| November 23, 2020 | education
Using the lens formula, we find:
formula: 1 / F = (n – 1) * (1 / R1 + 1 / R2).
Designations: F – focal length, R1, R2 – radii of curvature).
1 / F = (1.5 – 1) * (1 / 0.2 + 1 / 0.2) = 5 (1 / m)
F = 1/5 = 0.2m.
Answer 0.2 m.
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