What is the force acting from the side of the magnetic field with an induction of 50 mT on a conductor

| May 15, 2021 | education

What is the force acting from the side of the magnetic field with an induction of 50 mT on a conductor with a current, if the vector of the magnetic induction of the field is perpendicular to the conductor? Conductor length 10 cm, current 10 A.

To find the magnitude of the force acting on the specified conductor from the side of the magnetic field, we apply the formula: Fa = B * I * l (sinα = sin 90º = 1, since the magnetic induction vector is perpendicular to the specified conductor).

Variables: B – magnetic induction (B = 50mT = 0.05T); I – current (I = 10 A); l is the length of the specified conductor (l = 10 cm = 0.1 m).

Calculation: Fa = B * I * l = 0.05 * 10 * 0.1 = 0.05 N.

Answer: The Ampere force acting on the indicated conductor is 0.05 N.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.