What is the force acting on a proton moving at a speed of 107 m / s in a magnetic field with

What is the force acting on a proton moving at a speed of 107 m / s in a magnetic field with an induction of 0.2 T perpendicular to the lines of induction.

The proton will be acted upon by the Lorentz force F = qvB * sin a, where q is the proton charge, v is the velocity, B is the induction. The angle a between the direction of the lines of force and the direction of the velocity is 90 degrees.
sin a = 1.
In our case, F = 1.6 * 10 ^ -19 C * 10 ^ 7 m / s * 0.2 T = 3.4 * 10 ^ -18 N.
Answer: 3.4 * 10 ^ -18 N.