What is the force acting on a proton moving at a speed of 2000 km / s in a uniform magnetic

What is the force acting on a proton moving at a speed of 2000 km / s in a uniform magnetic field, with an induction of 0.1 T. Proton moves at an angle of 60 degrees to the lines of magnetic induction of the field.

Given:
V = 2000 km / s;
B = 0.1 T;
The angle is 60 degrees.
Find: F.
Decision:
In order to find the answer, we will use this formula, since it denotes the Lorentz force, which, as you know, acts on a charge in a magnetic field.
F = q * v * B * sina.
This formula contains a constant that is always equal to the same value: q. It denotes the charge of the proton and is equal to 1.6 * 10 ^ -19 cells.
Substitute all the values in the formula and get the answer.
F = 1.6 * 10 ^ -19 * 2 * 10 ^ 6 * 0.1 * 05 = 1.6 * 10 ^ -14 H.
Answer: 1.6 * 10 ^ -14