What is the force of gravitational attraction between two identical billiard

| August 2, 2021 | education

What is the force of gravitational attraction between two identical billiard balls at the moment of collision? Each ball weighs 200 g, diameter 4 cm.

To find the value of the force of universal attraction between colliding billiard balls, we will use the formula (we take into account that the billiard balls are the same): Fgr = G * msh ^ 2 / r ^ 2 = G * msh2 / d ^ 2.

Variables and constants: G – gravitational constant (G ≈ 6.67 * 10 ^ -11 m2 / (s2 * kg)); msh is the mass of a billiard ball (mw = 200 g = 0.2 kg); d – distance between centers, ball diameter (d = 4 cm = 0.04 m).

Calculation: Fgr = G * msh ^ 2 / d ^ 2 = 6.67 * 10 ^ -11 * 0.2 ^ 2 / 0.04 ^ 2 = 1.6675 * 10 ^ -9 H = 1.6675 nN.

Answer: The force of worldwide attraction between colliding billiard balls is 1.6675 nN.



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