What is the force of gravity acting on 6 liters of water (water density 1000kg / m3)?

To find the value of the force of gravity acting on 6 liters of water, we use the formula: Ft = P = m * g = ρw * V * g.

Variables and constants: ρw is the density of the taken water (by condition we take ρw = 1000 kg / m3); V – volume (V = 6 l = 0.006 m3); g – acceleration due to gravity (g = 9.81 m / s2).

Calculation: Ft = ρw * V * g = 1000 * 0.006 * 9.81 = 58.86 N.

Answer: The force of gravity acts on 6 liters of water at 58.86 N.

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