What is the force of gravity acting on an astronaut weighing 70 kg in a spacecraft moving at an altitude

| August 8, 2021 | education

What is the force of gravity acting on an astronaut weighing 70 kg in a spacecraft moving at an altitude of 300 km from the Earth’s surface? The mass of the Earth is 6 * 10 ^ 24 kg, the radius of the Earth is 6400 km.

m = 70 kg.
Rorb = 300 km = 300000 m.
Rz = 6400 km = 6400000 m.
G = 6.67 * 10 ^ -11 H * m ^ 2 / kg ^ 2.
Mz = 6 * 10 ^ 24 kg.
F -?
According to the law of universal gravitation, the force of attraction F between the astronaut and the Earth is determined by the formula: F = G * m * Mz / R ^ 2. Where G is the gravitational constant, m is the mass of the astronaut, Mz is the mass of the Earth, R is the distance between the astronaut and the center of the Earth.
R = Rorb + Rz.
F = G * m * Mz / (Rorb + Rz) ^ 2.
F = 6.67 * 10 ^ -11 H * m ^ 2 / kg ^ 2 * 70 kg * 6 * 10 ^ 24 kg / (300000 m + 6400000 m) ^ 2 = 624 N.
Answer: the gravity of an astronaut in orbit F = 624 N.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.