What is the force of gravity on a 10 x 8 x 5 cm copper bar?

Problem data: L (the length of the copper bar taken) = 10 cm (in SI L = 0.1 m); B (bar width) = 8 cm (in SI B = 0.08 m); s (thickness) = 5 cm (in SI s = 0.05 m).

Reference values: g (acceleration due to gravity) ≈ 10 m / s2; ρm (copper density) = 8900 kg / m3.

To calculate the required gravity, which acts on the taken copper bar, we use the formula: Ft = m * g = ρm * V * g = ρm * L * B * s * g.

Let’s calculate: Ft = 8900 * 0.1 * 0.08 * 0.05 * 10 = 35.6 N.

Answer: The force of gravity is 35.6 N.