What is the force of gravity on a 10x8x5cm copper bar?

Given:

a = 10 centimeters = 0.1 meters – the length of the copper bar;

b = 8 centimeters = 0.08 meters – the width of the copper bar;

c = 5 centimeters = 0.05 meters – the height of the copper bar;

ro = 8900 kg / m ^ 3 – copper density;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine which force of gravity F (Newton) acts on a copper bar.

Find the volume of a copper bar:

V = a * b * c = 0.1 * 0.08 * 0.05 = 0.0004 m ^ 3.

Then its mass will be equal to:

m = ro * V = 8900 * 0.0004 = 3.56 kilograms.

The force of gravity will be equal to:

F = m * g = 3.56 * 10 = 35.6 Newtons.

Answer: A gravity force equal to 35.6 Newtons acts on a copper bar.