What is the force of pressure on the pump piston at a water delivery height of 25 m, if the piston area is 100 cm3?

Let’s translate all the values ​​from given to the SI system:
S = 100 cm2 = 0.01 m2
According to Pascal’s law:
The hydrostatic pressure inside the liquid at any depth does not depend on the shape of the vessel in which the liquid is located, and is equal to the product of the density of the liquid, the acceleration of gravity and the depth at which the pressure is determined:
P = ρ * g * h, where ρ is the density of the liquid, g is the free fall acceleration of a body raised above the Earth g = 9.8 m / s2, h is the depth of immersion in the liquid.
The force of water pressure on the piston:
F = P * S, where S is the area of ​​the piston.
Let’s substitute the formula for pressure in the formula for determining the force:
F = P * S = ρ * g * h * S
Let’s determine the density of water according to the reference book:
ρ = 1000 kg / m³
Substitute the numerical values ​​and calculate the force:
F = ρ * g * h * S = 1000 * 9.8 * 25 * 0.01 = 2450 N.
Answer: the force of water pressure on the pump piston is 2540 N.