# What is the force of pressure that compresses the Magdenburg hemispheres

**What is the force of pressure that compresses the Magdenburg hemispheres, from which air is pumped out, if the surface area of the hemispheres is 1500 cm ^ 2.**

By definition, pressure p is equal to the ratio of the magnitude of the pressing force F to the surface area S, on which it presses p = F: S, then:

F = p ∙ S.

To find out what kind of pressure force compresses the Magdenburg hemispheres, from which air is pumped out, it is necessary to take into account that these plates are compressed by atmospheric pressure. The value of normal atmospheric pressure is p = 101 325 Pa. It is known from the problem statement that the surface area of the Magdenburg hemispheres is S = 1500 cm ^ 2 = 0.15 m ^ 2. Substitute the values of the quantities into the calculation formula:

F = 101 325 Pa ∙ 0.15 m ^ 2; F ≈ 15200 N = 15.2 kN.

Answer: The Magdenburg hemispheres are compressed by a force of 15.2 kN.