What is the force required to hold a 270g bar with a volume of 30cm3 in water?

To find out the force required to hold the taken bar, we project the acting forces onto the vertical axis: F + Fa – P = 0 and F = P – Fa = m * g – ρw * g * V = (m – ρw * V) * g …

Const: ρw – water density (ρw = 10 ^ 3 kg / m3); q – acceleration due to gravity (q ≈ 10 m / s2).

Task data: m – mass (m = 270 g = 0.27 kg); V is the volume of the bar (V = 30 cm3 = 3 * 10 ^ -5 m3).

Calculation: F = (m – ρw * V) * g = (0.27 – 10 ^ 3 * 3 * 10 ^ -5) * 10 = 2.4 N.

Answer: Requires a force of 2.4 N.