What is the force that holds a 6m³ marble beam in water?

Initial data: V (volume of the marble beam) = 6 m3.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2; according to the condition ρw (water density) = 1000 kg / m3; ρm (density of marble) = 2700 kg / m3.

The force applied to hold the marble beam in water is determined by the formula: F = Ft – Fa = m * g – ρw * g * V = ρm * V * g – ρw * g * V = V * g * (ρm – ρv).

Let’s calculate: F = 6 * 10 * (2700 – 1000) = 102000 N (102 kN).

Answer: The force holding the marble beam is 102 kN.