What is the force that stretched a vertically positioned spring with a stiffness of 120 N / m by 2 cm?
| September 10, 2021 | education
Given:
x = 2 cm = 0.02 m;
k = 120 N / m;
F -?
Solution: an elastic force acts on the spring: F = k * x;
F = 0.02 * 120 = 2.4 N.
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