What is the force with which two opposite charges equal to 1 μC each, placed

What is the force with which two opposite charges equal to 1 μC each, placed at a distance of 0.3 m from each other, are attracted?

Data: qз = | qз1 | = | qз2 | – module of each charge (qz = 1 μC = 10 ^ -6 C); r is the distance between the presented opposite charges (r = 0.3 m).

Const: k – coefficient of proportionality (k = 9 * 10 ^ 9 N * m2 / Kl2).

To find out the desired force of attraction of the presented unlike charges, consider the formula (use of Coulomb’s): Fк = k * qz1 * qz² / r² = k * qz² / r².

Let’s calculate: Fк = k * qz² / r² = 9 * 10 ^ 9 * (10 ^ -6) ² / 0.32 = 0.1 N.

Answer: The presented opposite charges must attract with a force of 0.1 N.