What is the frequency and period of the wind turbine wheel, if the wheel has made 50 revolutions in 2 minutes?

t = 2 min = 120 s.
N = 50
f -?
T -?
f = N / t
f = 50/120 s = 0.41 Hz
The frequency of oscillations f is the number of oscillations per unit of time.
T = t / N.
T = 120 s / 50 = 2.4 s.
The oscillation period T is the time of one complete oscillation.
Answer: f = 0.41 Hz, T = 2.4 s.

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