What is the greater angle of an isosceles trapezoid if it is known that the difference between the opposite angles = 68?

Since the trapezoid is isosceles, its angles at the bases are equal.

Let the angle ABC = X0, then, since the sum of the angles at the side of the trapezoid is 180, the angle BAD = 180 – X.

Since the angle BCD = ABC = X0, then the angle BCD – BAD = X – (180 – X) = 68.

2 * X = 68 + 180 = 248.

X = ABC = 248/2 = 124.

Angle BAD = 180 – 124 = 56.

Answer: The larger angle of the trapezoid is 124.



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