What is the greatest force a hydraulic press piston can develop with an area of 2000 mm2

What is the greatest force a hydraulic press piston can develop with an area of 2000 mm2, if the permissible pressure in it is exactly 300 N / cm2.

At the maximum allowable pressure, if you do not take into account the effect of the friction force, the greatest force that the hydraulic press piston develops can be calculated by the formula:
F = P * S, where P is the allowable pressure (P = 300 N / cm ^ 2), S is the surface area of the piston (S = 2000 mm ^ 2 = 20 cm ^ 2).
F = P * S = 300 * 20 = 6000 N = 6 * 10 ^ 3 N = 6 kN.
Answer. The largest force is 6 kN.