What is the height of a column of alcohol, if this one so produces a pressure of 10 ^ 5Pa?

Given:

P = 10 ^ 5 Pascal = 100000 Pascal – the pressure that the column of alcohol produces;

g = 10 Newton / kilogram – acceleration of gravity;

ro = 800 kilograms / cubic meter – the density of alcohol.

It is required to determine h (meter) – the height of a column of alcohol that produces a pressure equal to P.

To determine the height of the post, you need to use the following formula:

P = ro * g * h, from here we find that:

h = P / (ro * g);

h = 100000 / (800 * 10);

h = 100000/8000 = 100/8 = 12.5 meters.

Answer: The height of the kerosene column is 12.5 meters.