What is the highest and lowest pressure that a 10 x 5 x 8 cm tin bar can create?

Given: the dimensions of the bar are 10x5x8 cm (0.1×0.05×0.08 m).

Constants: ρ (tin density) = 7300 kg / m3; g (acceleration due to gravity) ≈ 10 m / s2.

Pressure formula: P = Ft / S and the bar will exert the smallest pressure at the maximum support area, and the largest – at the minimum.

1) Gravity: Fт = m * g = ρ * V * g = 7300 * (0.1 * 0.05 * 0.08) * 10 = 29.2 N.

2) The highest pressure: P1 = Ft / S1 = 29.2 / (0.05 * 0.08) = 7300 Pa.

3) The smallest pressure: P2 = Ft / S2 = 29.2 / (0.1 * 0.08) = 3650 Pa.