What is the impulse of a bullet with a mass of 10 grams, which is ejected from the barrel of an assault rifle at a speed of 500 m / s?

The momentum of the body p is equal to p = mv, we have both mass and velocity, so we just need to substitute the values of mass and velocity, but first we convert 10 gr into kg and 500 m / s into km / h, and we get 0, 01 kg and 138.8 km / h, and then it turns out
p = 0.01 * 138.8 = 1.38 (kg * m / s)
Answer: p = 1.38 (kg * m / s)