What is the inductance of a coil if at a current of 0.3 kA its energy is 15 J?
| May 22, 2021 | education
To find the value of the inductance of the used coil, we apply the formula: W = L * I ^ 2/2, from where we express: L = 2W / I ^ 2.
Values of variables: W – energy of the used coil, magnetic field (W = 15 J); I is the current in the coil (I = 0.3 kA = 300 A).
Let’s calculate: L = 2W / I ^ 2 = 2 * 15/300 ^ 2 = 3.333 * 10-4 H = 333.3 μH.
Answer: The inductance of the coil is 333.3 μH.
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