What is the inductance of the choke if, at a rate of change in the current strength of 80 A / s
| May 2, 2021 | education
What is the inductance of the choke if, at a rate of change in the current strength of 80 A / s, the EMF of self-induction is 30 V?
Initial data: ΔI / Δt (change in current strength in the inductor) = 80 A / s; ε (EMF of self-induction arising in the choke) = 30 V.
We express the inductance of the choke from the formula: ε = | L * ΔI / Δt |, whence L = ε / (ΔI / Δt).
Let’s calculate: L = 30/80 = 0.375 H.
Answer: The inductance of the choke is 0.375 H (375 mH, 375,000 μH).
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